An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder is Pf=1.24 atm. What is the enthalpy change for this process? ΔH =

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

Whereas the change in the internal energy is computed by:

So we compute the initial and final temperatures for one mole of the ideal gas:

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

Then, the volume-pressure product in Joules:

Finally, the change in the enthalpy for the process:

Best regards.

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.