7. What volume of a 0.10 mol/l HCl solution is needed to neutralize 10 ml of a 0.15 mol/l LiOH solution (5 points)

The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is LiOH.

We are given:

Putting values in above equation, we get:

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

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