A stock solution of HNO3 is prepared and found to contain 14.9 M of HNO3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, what is the concentration of the diluted solution

Explanation:

In this case, we have a dilution problem. So, we have to use the dilution equation:

Now, we have to identify the variables:

Now, we have different units for the volume, so we have to do the conversion:

Now we can plug the values into the equation:

I hope it helps!

answer: mole of the gas

answer: mole of the gasexplanation:

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )