Write an equation showing how to prepare 3-bromo-4-methylacetophenone from toluene and any necessary organic or inorganic reagents. If an ortho, para mixture is formed in any step of your synthesis, assume that you can separate the two isomers. 1. Isopropylbenzene
2. p-Iso-propylbenzenesulfonic acid
3. 2-bromo-2-phenylpropane
4. 4-tert-Butyl-2-nitrotoulene
5. m-Chloroacetophenone
6. p-Chloroacetophenone
7. 3-Bromo-4methylacetophenone
8. 2-Bromo-4-ethyltoulene
9. 1-Bromo-3-nitrobenzene
10. 1-Bromo-2,4-dinitrobenzene
11. 3-Bromo-5-nitrobenzoic acid
12. 2-Bromo-4-nitrobenzoic acid
13. Diphenylmethane
14. 1-phenyloctane
15. 1-phenyl-1-octene
16. 1-phenyl-1-octyne

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

your parents i think this could be it

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it's all four options.