CsCl crystallizes in a unit cell that contains the Cs ion at the center of a cube that has a Cl- at each corner. Each unit cell contains Cs ion(s) and Cl- ion(s), respectively.

The given question is incomplete, the complete question is:

CsCl crystallizes in a unit cell that contains the Cs+ ion at the center of a cube that has a Cl- at each corner. Each unit cell contains Cs+ ions and Cl-, ions, respectively.

a. 1 and 8

b. 2 and 2

c. 2 and 1

d. 2 and 4

e. 1 and 1

The correct answer is option e, that is, 1 and 1.

Explanation:

A regular and a small geometric unit of a crystal that illustrates the repeating pattern of the crystal lattice is termed as a unit cell. Based on the given question, crystallization of CsCl takes place in a unit cell that comprises the ion of Cs+ at the center of a cube, which possesses Cl- at every corner.  

In the given case, in the center of the lattice one atom of Cs is present, therefore, there is one ion of Cs for one unit cell. It is known that there are 8 corners of a cube, and Cl- ion is situated at each corner. So,  

8 corners * (1 Cl ion/8 corners) = 1 Cl ion

Hence, the ratio of Cs+ : Cl- is 1:1.  

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2