Use Hess's law and the following equations to calculate the ΔHreaction for the reaction CO(g) + 3H2(g) CH4(g) + H2O(g). (Show your work.) (4 points) • C(s) + O2(g) CO(g) ΔH = –110.5 kJ • C(s) + 2H2(g) CH4(g) ΔH = –74.85 kJ • H2(g) + O2(g) H2O(g) ΔH = –241.83 kJ

The enthalpy of reaction is, -206.18 kJ

Explanation:-

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The final reaction is

The intermediate balanced chemical reaction will be,

(1)    

(2)    

(3)    

Now adding (2) and (3) and subtracting (1) , we get :

Therefore, the enthalpy of reaction is, -206.18 kJ

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8