Someone help me please I need to finish this by today

Option A

Explanation:

First calculate the moles of each reactant,

Moles of SO2 = 544.5 * 1 mole / 64.06 g,

Moles of SO2 = ( About ) 8.5 Moles,

Moles of O2 = 160 * 1 mole / 32 g,

Moles of O2 = 5 Moles,

Now the molar ratio of SO2 to SO3 would be 2 : 2, so that you could say SO3 = ( About ) 8.5 Moles. Respectively, the molar ratio of O2 to SO3 would be 1 : 2, so that SO3 = 5 Moles. The limiting reactant would thus be SO2.

Using that information, we can now calculate the yield of SO3,

Yield of SO3 = 8.5 mole * 80.06 g / 1 mole = 680.5 grams,

Percent Yield = ( 382 / 680.5 ) * 100 = 56.1 %

Solution = Option A

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

2b2t

explanation:

2b2t