How much total energy is released to cool 28.3 g of steam (water vapor) at 100.0°C to liquid water at 25.5°C? Water has a heat of vaporization of ± 40.7 kJ/mol and a specific heat of 4.184 J/g°C.

Explanation:

Hello,

In this case, for the computation of the total energy, we must consider two processes:

1. Condensation of steam (heat of condensation is the negative of heat of vaporization).

2. Cooling of hot water (we use the specific heat of water).

Thus, we write:

For each term, we have:

Therefore, the total energy results:

Regards.

answermeridional ;