Which of the following best explains the polarity of water (H2O)? OA.
Since the oxygen atom has more electrons than the hydrogen atoms, it is negatively charged.
ОВ.
Electrons are more attracted to the oxygen atom, so there is a partial negative charge on the oxygen atom.
OC.
Since there are two positive hydrogen atoms and only one negative oxygen atom, the water molecule is positively
charged
OD
Protons are more attracted to the hydrogen atoms, so the hydrogen atoms become positively charged.

B). Electrons are more attracted to the oxygen atom, so there is a partial negative charge on the oxygen atom.

Explanation:

The above statement most aptly describes the polarity or uneven distribution of the density of electrons. In water, two hydrogen atoms and one atom of oxygen leading to the formation of polar covalent bonds. Thus, there is the presence of a partial negative charge close to the oxygen atom and partial positive charge near the hydrogen atom as the former has unshared pair of electrons. This polarity of water allows it to dissolve sugar or other ionic substances in it. Thus, option B is the correct answer.

its mg hope this

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: