A sample of 0.35 L of argon gas (at a temperature of 13 oC and a pressure of 568 torr) is heated to 156 oC and a new pressure of 897 torr. Calculate the new volume of the gas.

The new volume of the gas is 0.332 liters.

Explanation:

Let suppose that argon behaves ideally, the equation of state of the ideal gas is:

Where:

- Pressure, measured in torr.

- Volume, measured in liters.

- Molar quantity, measured in moles.

- Temperature, measured in kelvins.

- Ideal gas constant, measured in .

Since gas sample is a closed system experimenting a heating process, that is, molar quantity remains constant, the following relationship is derived from the equation of state described above:

Where:

, - Initial and final pressures, measured in torr.

, - Initial and final volumes, measured in liters.

, - Initial and final temperatures, measured in kelvins.

Now, the final volume of the gas is found:

If , , , and , the new volume of the gas is:

The new volume of the gas is 0.332 liters.

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