To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate in a 100 mL volumetric flask and then fills with water to the 100 mL mark. How many moles of acetic acid are present in this buffer?

There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

Thus there are 0.00269 moles of acetic acid in buffer.

where's the diagram?

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890