When 6.25 grams of pure iron are allowed to react with oxygen, a black oxide forms. if the product weighs 8.15g, what is the empirical formula of the oxide?

Moles Fe = 6.25 g / 55.847 g/mol=0.112

mass O = 8.15 - 6.25 =1.90 g

moles O = 1.90 g/ 15.999 g/mol=0.119

the ratio is 1 : 1 and the compound is FeO ( iron (II) oxide)

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