Calcium carbonate is a common ingredient in antacids that reduces the discomfort associated with acidic stomach or heartburn. Stomach acid is hydrocholoric acid, HCl. What volume in milliliters (mL) of an HCl solution with a pH of 1.52 can be neutralized by 27.0 mg of CaCO3

17.86mL of the HCl solution

Explanation:

The reaction of CaCO₃ with HCl is:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

The concentration of HCl with a pH of 1.52 is:

pH = 1.52 = -log [H⁺]

[H⁺] = 0.0302M = [HCl]

27.0mg = 0.0270g of CaCO₃ (Molar mass: 100.09g/mol) are:

0.0270g of CaCO₃ ₓ (1mol / 100.09g) = 2.70x10⁻⁴ moles of CaCO₃

Moles of HCl to react completely with these moles of CaCO₃ are:

2.70x10⁻⁴ moles of CaCO₃ ₓ (2 mol HCl / 1 mol CaCO₃) =

5.40x10⁻⁴ moles of HCl

As the concentration of HCl is 0.0302M, volume in 5.40x10⁻⁴ moles is:

5.40x10⁻⁴ moles of HCl * (1L / 0.0302mol) = 0.01786L =

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

i believe the answer is a.