A certain shade of blue has a frequency of 7.30×1014 Hz. What is the energy of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.

The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules

Explanation:

A photon is an elementary particle that, according to the principles of quantum physics, makes up light.

A photon is characterized by a wavelength, denoted by λ, or, by an energy, denoted by E.

The relationship between the amount of energy (E) transported by the photon, and its frequency (v), is determined by:

E= h*v

where, as mentioned, E is the energy v is the frequency and h is the Planck constant, whose value is 6,626 * 10⁻³⁴ Joules-sec.

In this case, the frecuency is 7.30*10¹⁴ Hz. Then:

E=6,626 * 10⁻³⁴ Joules-sec* 7.30*10¹⁴ Hz

Solving:

E= 4.84*10⁻¹⁹ Joules

The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.