A steel bottle contains argon gas at STP. What is the final pressure if the temperature is changed to 115°C?

Final pressure is 1.42atm

Explanation:

Based on Gay-Lussac's law, pressure of a gas is directely proportional to its absolute temperature. The equation of this law is:

P₁T₂ = P₂T₁

Where P is pressure and T is absolute temperature of 1, initial state and 2, final state of the gas.

In the problem, initial conditions are Standard Temperature and Pressure, STP, that are 1 atm and 273.15K.

If the final temperature is 115°C = 388.15K (115°C + 273.15 = 388.15K), using Gay-Lussac's law:

P₁T₂ = P₂T₁

1atmₓ388.15K = P₂ₓ273.15K

1.42atm = P₂

i dont know

explanation:

po-215 i got it right on the quiz