How many moles of aqueous magnesium ions and chloride ions are formed when 0.240 mol of magnesium chloride dissolves in water

1. 0.240 mole of magnesium ion, Mg^2+

2. 0.48 mole of chloride ion, Cl^-

Explanation:

We'll begin by writing the balanced dissociation equation for magnesium chloride. This is given below:

MgCl2(aq) —> Mg^2+(aq) +2Cl^-(aq)

1. Determination of the number of mole of magnesium ion, Mg^2+ obtained from the dissolution 0.240 mol of magnesium chloride, MgCl2 in water. This is illustrated below:

From the balanced equation above,

1 mole of MgCl2 produced 1 mole of Mg^2+.

Therefore, 0.240 mole of MgCl2 will also produce 0.240 mole of Mg^2+.

Therefore, 0.240 mole of magnesium ion, Mg^2+ is produced.

2. Determination of the number of mole of chloride ion, Cl^- obtained from the dissolution 0.240 mol of magnesium chloride, MgCl2 in water. This is illustrated below:

From the balanced equation above,

1 mole of MgCl2 produced 2 moles of Cl^-.

Therefore, 0.240 mole of MgCl2 will produce = (0.240 x 2) = 0.48 mole of Cl^-.

Therefore, 0.48 mole of chloride ion, Cl^- is produced.

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