How many moles of sulfur trioxide will be produced when the complete combustion of 100.0 g of sulfur dioxide takes place

1.563 moles of SO3.

Explanation:

We begin by calculating the number of mole present in 100g of sulphur dioxide, SO2. This can be obtained as follow:

Molar mass of SO2 = 32 + (16x2) = 64g/mol

Mass of SO2 = 100g

Mole of SO2 =..?

Mole = mass/Molar mass

Mole of SO2 = 100/64

Mole of SO2 = 1.563 mole

Now, we can obtain the number of mole of sulphur trioxide, SO3 produce from the reaction as follow:

2SO2 + O2 —> 2SO3

From the balanced equation above,

2 moles of SO2 reacted to produce 2 moles of SO3.

Therefore, 1.563 moles of SO2 will also react to produce 1.563 moles of SO3.

Therefore, 1.563 moles of SO3 is obtained from the reaction.

i'm pretty sure it is letter c.) car

5.6⋅10−^19  j

do you need the explaination?