How many moles of 0.225 M CaOH2 are present in 0.350 L of solution? Calculate the number of moles of solute (CaOH2)

( M CaOH2)
(0.350 L
) = mol CaOH2

Answer : The number of moles of solute is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

Now put all the given values in this formula, we get:

Therefore, the number of moles of solute is, 0.0788 moles.

(0.225 M CaOH2) x (0.350 L) = 0.0788 mol CaOH2

Explanation:

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For the second question: How many grams of CaOH2 are in this solution?

The molar mass of CaOH2 is 58.093 g/mol.

(0.0787 mol CaOH2) x (58.093 g/mol) = 4.57g CaOH2

Explanation:

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explanation: