This compound can be made by combining gaseous carbon monoxide with hydrogen gas (with this compound as the only product). What is the maximum mass of this compound that can be prepared if 8.0 kg of hydrogen gas react with 59.0 kg of carbon monoxide gas

Maximum mass of compound produced = 64 Kg

Explanation:

Carbon monoxide react with hydrogen to produce methanol. Equation for the reaction is given as follows:

CO(g) + 2H₂(g) > CH₃OH(l)

From the equation of reaction, 1 mole of CO reacts with 2 moles of Hydrogen gas to produce 1 mole of methanol.

Molar mass of CO = 28 g

Molar mass of H₂ = 2 g

Molar mass of methanol = 32 g

Therefore, 28 g of CO reacts with  4 g of H₂ to produce 32 g of methanol

8.0 Kg of hydrogen will react with 8 * (28/4) Kg of CO = 56 Kg of CO.

therefore, hydrogen is the limiting reactant in the reaction under consideration.

8.0 Kg of Hydrogen will react with 56 Kg of CO to produce 8 * (32/4) Kg of methanol =  64 Kg of methanol

Therefore, maximum mass of compound produced = 64 Kg

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"