What is the boiling point of a solution that contains 3 moles of KBr in 2000 g of water? A. 97°C

B. 103°C

C. 101.5°C

D. 99.7°C

C. 101.5°C

Explanation:

The computation of the boiling point of a solution is shown below:

As we know that

where,

i = Factor of Van’t Hoff i.e 2KBr

K_b = Boiling point i.e 0.512° C

m = molality  

Now place the values to the above formula

So, the boiling point is

After solving this, the t is

= 100° C + 1.536° C

= 101.536° C

Hence, the correct option is C.

that tool would be a compass

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.