Consider the combustion of butane: 2C4H10(g)+ 1302(g)= 8CO2(g) +10H2O(1)
if
you have 50.0 gr...
Chemistry, 17.07.2020 03:01 trevorhenyan51
Consider the combustion of butane: 2C4H10(g)+ 1302(g)= 8CO2(g) +10H2O(1)
if
you have 50.0 grams
butane, how many moles
of butane do you have?
use the following atomic
weights C = 17.0 g/mole; H
1.0g/mole; O= 16. Og/mole
Answers: 3
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