Chemistry, 16.07.2020 16:01 amberell1234

5. How many atoms and molecules of sulphur are present in 64.0 g of sulphur (S 8 )?

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Answer from: lacourboud20005

There are $1.202\times 10^{24}$ atoms and $1.502\times 10^{23}$ molecules in the compound.

Explanation:

The molar mass of the sulphur is $32.065\,\frac{g}{mol}$ . The Avogradro's Law states that exists $6.022\times 10^{23}\,\frac{atom}{mol}$ . The quantity of atoms in a quantity of mass is derived from dividing the mass by the molar mass and multiplying it by the Avogadro's Number. That is:

$n_{atom} = m_{S}\cdot \frac{n_{A}}{M_{S}}$

Where:

$m_{S}$ - Mass of the sample, measured in grams.

$n_{A}$ - Avogadro's Number, measured in atoms per mole.

$M_{S}$ - Molar mass of the sulphur, measured in grams per mole.

If $m_{S} = 64\,g$ , $n_{A} = 6.022\times 10^{23}\,\frac{atoms}{mol}$ and $M_{S} = 32.065\,\frac{g}{mol}$ , then:

$n_{atom} = (64\,g)\cdot \left(\frac{6.022\times 10^{23}\,\frac{atoms}{mol} }{32.065\,\frac{g}{mol} }\right)$

$n_{atom} = 1.202\times 10^{24}\,atoms$

There are $1.202\times 10^{24}$ atoms in the compound.

Now, the molecular weight of the compound is:

$M_{S_{8}} = 8\cdot \left(32.065\,\frac{g}{mol} \right)$

$M_{S_{8}} = 256.52\,\frac{g}{mol}$

The quantity of molecules in a quantity of mass is derived from dividing the mass by the molecular weight and multiplying it by the Avogadro's Number. That is:

$n_{molecule} = m_{S_{8}}\cdot \frac{n_{A}}{M_{S_{8}}}$

Where:

$m_{S_{8}}$ - Mass of the sample, measured in grams.

$n_{A}$ - Avogadro's Number, measured in atoms per mole.

$M_{S_{8}}$ - Molecular weight of the compound (octosulphur), measured in grams per mole.

If $m_{S_{8}} = 64\,g$ , $n_{A} = 6.022\times 10^{23}\,\frac{molecules}{mol}$ and $M_{S_{8}} = 256.52\,\frac{g}{mol}$ , then:

$n_{molecule} = (64\,g)\cdot \left(\frac{6.022\times 10^{23}\,\frac{molecules}{mol} }{256.52\,\frac{g}{mol} }\right)$

$n_{molecule} = 1.502\times 10^{23}\,molecules$

There are $1.502\times 10^{23}$ molecules in the compound.

Answer from: Quest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

Answer from: Quest

Because it was a dramatically big guy

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