if 75 kj of heat is transferred to 1200 g liquid water at 36 C, what would the new temperature of the water be?

θ2 = 50.93°

Explanation:

Given the following :

Quantity of heat = 75kj = 75 × 1000 = 75000J

Mass of liquid water = 1200g

Temperature of water = 36°C

Using the relation :

Q = mc∆T ; where

Q = heat energy (Joules, J)

m = mass of a substance (kg)

c = specific heat (units J/g.°C)

∆T = change in temperature (θ2 - θ1)

(The specific heat capacity of liquid water(c)

is 4.186 J/g.°C

Inputting values:

Q = mc(θ2 - θ1)

75000 = 1200 × 4.186 (θ2 - 36)

75000 = 1200 × 4.186(θ2) - 150.696

75000 = 5023.2(θ2) - 180835.2

75000 + 180835.2 = 5023.2θ2

255835.2 = 5023.2(θ2)

θ2 = 255835.2 / 5023.2

θ2 = 50.93°

- decrease the number of plants and animals living in the water.

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.