Given the specific heat for aluminum is 0.900 J/g.°C, how much heat is released when a 3.8 g sample of Al cools from 450.0°C to 25°C?
A. 1.5 kJ
B. 54 J
C. 60J
D. 1.7 kJ
E. 86 J

Q = 1.5 kJ

Explanation:

It is given that,

The specific heat for aluminum is 0.900 J/g°C

Mass of sample, m = 3.8 g

Initial temperature,

Final temperature,

We need to find the heat released. The amount of heat released is given by the formula:

or

So, the correct option is (A) i.e. 1.5 kJ.

i believe the answer is a.