Given the following thermochemical data C(s) + ½O2(g) ---> CO(g) ∆H1 = -111 kJ/mol C(s) + O2(g) ---> CO2(g) ∆H2 = -395 kJ/mol What is the ∆Hr for the reaction: CO(g) + ½O2(g) ---> CO2(g) ∆Hr = ?

The enthalpy of the reaction asked is -284 kJ/mol.

Explanation:

Given:

..[1]

...[2]

To find ; of following reaction :

..[3]

Using Hess's Law:

[2] - [1] = [3]

The enthalpy of the reaction asked is -284 kJ/mol.

quartz

explanation:

the answer to your question is c