A reversible reaction has an equilibrium constant of 0.75. If the forward rate constant is 0.62 mol/L/s, what's the reverse reaction rate constant? A. 0.910
B. 0.827
C. 1.010
D. 1.210

B.) 0.827

Explanation:

Given the following :

Equilibrium constant (k) = 0.75

Forward rate constant = 0.62 mol/L/s

Backward rate constant =?

The equilibrium constant denited as 'k' is the proportion of the forward rate constant and the reverse rate constant.

Mathematically,

K = [forward rate constant / Reverse rate constant]

k = 0.75 ; forward rate constant = 0. 62mol/L/s

0.75 = [ 0.62mol/L/s ÷ reverse rate constant]

Reverse rate constant * 0.75 = 0.62mol/L/s

Reverse rate constant = (0.62mol/L/s ÷ 0.75)

Reverse rate constant = 0.8266mol/L/s

Reverse rate constant = 0.827mol / L/s

answer; ///(d) the correct answer is double or triple

23.5

23.5

47.0