In reaction NH3 →3H2 + N2, how many moles of N2 formed if 2.81 g NH3 dissociate? Show work!

0.0826 mol (corrected to 3 sig. fig.)

Explanation:

First, balance the equation:

2NH3 →3H2 + N2

Take the atomic no. of N=14.0, and H=1.0,

no. of moles = mass / molar mass

So, no. of moles of NH3 dissociated = 2.81 / (14.0+1.0x3)

= 0.165294117mol

From the equation, the mole ratio of NH3:N2 = 2:1, meaning for every 2 moles of NH3 dissociated, one mole of N2 is formed.

So, using this ratio, the no. of moles of N2 formed will be 0.165294117 / 2

=0.0826 mol (corrected to 3 sig. fig.)

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i think the answer is terrae but not 100 percent sure. ▓▬▬ §