An aqueous solution of glucose (MM = 180.2 g/mol) has a molality of 2.27 m and a density of 1.20 g/mL. What is the molarity of glucose in the solution? **Any help would be greatly appreciated!**

Molarity of the glucose solution = 2.72 mol/L

Explanation:

Molality of a solution is defined as the number of moles of solute per kilogram of solvent.

Therefore , a 2.27 molal solution of glucose contains 2.27 moles of glucose in 1 Kg of solvent

Density of solution = 1.20 g/mL

The volume occupied by 1 Kg or 1000 g solution = mass/density

Volume of 1000 g solution = 1000 g/1.20 g/ml = 833.3 mL

Number of moles of glucose present in the solution = 2.27 moles

Molarity = number of moles / volume(L)

volume of solution in litres = 883.3/1000 = 0.8333 L

Molarity = 2.27 moles /0.8333 l = 2.72 mol/L

Therefore, molarity of the glucose solution = 2.72 mol/L

a is the answer

explanation:

which statement about trans-fatty acids is false?

a. the conversion of cis-fatty acids to trans-fatty acids is inhibited by the presence of antioxidants.

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there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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