Pentane, c5h12, will react as shown below:
(l) ++ h2o
h20(g)
1. balance the equation above by putting coefficients into each blank space.
1c5h12+ 5co2+ 6 h2o (this is what i got)
2. how many atoms of oxygen are in 144 grams of pentane?
step 1: 144g of c5h12*(1mole/72.17)= 1.995moles of c5h12
step 2: 1.995moles of c5h12*(8moles of o2/1mole of c5h12)= 15.962 moles of o2
step 3: 15.962 moles of o2*(6.02*10^23 atoms of o2/1mole of o2)= 9.609*10^24 atoms of o2 (i don't know if i did this right)
3. how many atoms of oxygen are in 192 grams of carbon dioxide gas?
step 1: 192 grams of co2 *(1mole of co2/44.01grams of co2)= 4.363 moles of co2
step two: 4.36moles of co2* ( 1 mole of o2/1mole of co2)=
step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of o2 (i don't know if this is correct.
4. a) circle one: true or false:
reactant you begin with fewer grams of is your limiting reactant.
b) if 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (use your reaction from the top of the first page)
need asap !