Among the following bonds, which would be the least polar? Electronegativity values are: Na = 0.9, O = 3.5, F = 4.0, Cl = 3.0, Br = 2.8, I = 2.5

e. Na_I

Explanation:

a.  Na–O

b.  Na–F

c.  Na–Cl

d.  Na–Br

e.  Na–I

Bond polarity can be calculated, examining the Pauling scale electronegativity values of the two atoms. The difference between these values will determine the predominant type of bond between the respective atoms.

Therefore, Na-I would be least polar bond. (The difference in the electronegativies of the two atom is least)

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j