The chemical formula for barium oxide is BaO. A chemist determined by measurements that 0.065 moles of barium oxide participate in a chemical reaction. Calculate the mass of barium oxide that participates.

9.97 g (corrected to 3 significant figures.)

Explanation:

mass = no. of moles x molar mass

Atomic mass of Barium = 137.327; oxygen = 15.999,

so the molar mass of BaO = 137.327 + 15.999

=153.326

Hence, the mass is

0.065 x 153.326

=9.97 g (corrected to 3 significant figures.)

9,97 g to the nearest hundredth.

Explanation:

Using the relative atomic masses of Barium and Oxygen:

1 mole of BaO has a mass of 137.327 + 16 = 153.327 g.

So 0.065 moles has a mass of 153.327 * 0.065

= 9.966 g.

c) always accurate

hope i u

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messi

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"