Pb2+(aq) + 2 e- --> Pb(s) Eo = -0.13V Zn2+(aq) + 2 e- --> Zn(s) Eo = -0.76V 9. Given the half-cell potentials above, when the reaction Zn(s) + Pb2+(aq) --> Zn2+(aq) + Pb(s) is made into a voltaic cell, the Ecell is: A. 0.63 V B. -0.63 V C. 0.89 D. 0.89

The is 0.63 V

Explanation:

In the given reaction :

Here Zn undergoes oxidation by loss of electrons, thus act as anode. Lead undergoes reduction by gain of electrons and thus act as cathode.

Where both are standard reduction potentials.

Thus the is 0.63 V

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)