A compound is found to contain 63.65 % nitrogen and 36.35 % oxygen by mass. The molar mass for this compound is 44.02 g/mol. The molecular formula for this compound is

THE MOLECULAR FORMULA FOR THE COMPOUND IS N20

Explanation:

To calculate the molecular formula for the compound, we follow the following steps:

Write out the percentage abundance of the individual elements

N = 63.65 %

O = 36.35 %

2. Divide the percentage composition by the atomic masses of the elements

N = 63.65 / 14 = 4.546

O = 36.35 / 16 = 2.272

3. Divide the values by the lowest value

N = 4.546 / 2.272 = 2.00

O = 2.202 / 2.272 = 1

4. The empirical formula of the compound will be:

N2O

5. Calculate the molecular mass

(N2O ) x = 44.02 g/mol.

(14 * 2 + 16) x = 44.02

(28 + 16) x = 44.02

44 x = 44.02

x = 44.02 / 44

x = 1

The molecular formula for the compound is N2O

idk what is it? is this a question that you know the answer or u dont

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.