At 298 K, Kc is 2.2×105 for the reaction F(g)+O2(g)⇌O2F(g) . What is the value of Kp at this temperature? Express your answer using two significant figures.

The value of Kp at this temperature is 9.0*10³

Explanation:

The equilibrium constant Kp describes the relationship that exists between the partial pressures of the reactants and products, while Kc represents the relationship that exists between the concentrations of the reactants and products that participate in the reaction.

The general relationship between the constants Kp and Kc results:

Kp=Kc*

In this case:

Replacing:

Kp=2.2*10⁵*

Solving:

Kp≅9.0*10³

The value of Kp at this temperature is 9.0*10³

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.