SUPPLEMENTARY QUESTION 1. Calculate the amount of heat (in calories) absorbed when 50 g of water at 20°C spreads over your skin and
warms to body temperature, 370C?

850 Calories.

Explanation:

The following data were obtained from the question:

Mass (M) = 50 g

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Specific heat capacity (C) of water = 1 cal/g°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature of water.

This can be obtained as follow:

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Change in temperature (ΔT) =..?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 37 – 20

Change in temperature (ΔT) = 17 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 50 g

Specific heat capacity (C) of water = 1 cal/g°C.

Change in temperature (ΔT) = 17 °C

Heat absorbed (Q) =..?

Q = MCΔT

Q = 50 x 1 x 17

Q = 850 Calories

Therefore, the heat absorbed is 850 Calories.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.