If the molarity of sugar is 1.1, what will the freezing point be?

The freezing point will be -2.046°C.

Explanation:

The freezing point depression equation is

Where;

= The temperature depression of the freezing point

= The constant of freezing point depression which is solvent dependent = 1.86°C/m

i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)

m = The molality of the solution = 1.1

Therefore, we have;

Therefore the freezing point will be 0 - 2.046°C = -2.046°C.

im pretty sure its b

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.