The decomposition of ethylene oxide(CH₂)₂O(g) → CH₄(g) + CO(g)is a first order reaction with a half-life of 58.0 min at 652 K. The activation energy of the reaction is 218 kJ/mol. Calculate the half-life at 629 K.

Half-life at 629K = 252.4min

Explanation:

Using Arrhenius equation:

And as Half-life in a first order reaction is:

We can convert the half-life of 58.0min to know K₁ adn replacing in Arrhenius equation find half-life at 629K:

K = 0.01195min⁻¹ = K₁

K₂ = 2.75x10⁻³ min⁻¹

And, replacing again in Half-life expression:

answer is a

explanation:

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.