calculate the number of moles equivalent to 25.0 gram of copper II sulfate pentahydrate [CuSO4 5H2O]

Explanation:

To calculate the number of moles in the given substance we use the equation

where

n is the number of moles

M is the molar mass

m is the mass of the substance

To calculate the number of moles we must first find the molar mass

That's

M( CuSO4 5H2O )

Cu = 64 , S = 32 , O = 16 H = 1

So we have

M( CuSO4 5H2O ) = 64 + 32 + (16 × 4) +

5( 2 + 16)

M( CuSO4 5H2O ) = 96 + 64 + 5(18)

M( CuSO4 5H2O ) = 160 + 90

M( CuSO4 5H2O ) = 250 g/mol

M( CuSO4 5H2O ) = 250 g/mol

mass of CuSO4 5H2O = 25 g

Substitute the values into the above formula

That's

We have the final answer as

Hope this helps you

☃️ Chemical formulae ➝

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

Atomic weight of Elements:

❍ Molecular weight of

= 64 + 32 + (16 × 4) + 5(2 × 16)

= 96 + 64 + 90

= 250 g/mol

❍ Given weight: 25 g

Then, no. of moles,

⇛ No. of moles = 25 g/ 250 g mol‐¹

⇛ No. of moles = 0.1 moles

⚘ No. of moles of Copper Sulphate pentahydrate in the given weight = 0.1 moles.

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samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

the correct answer is:

a. formation of precipitation