Consider the ligand field splitting of octahedral and tetrahedral complexes that we discussed in class. Draw the d-orbital splitting for an octahedral and a tetrahedral complex. Copper(I) complexes tend to be tetrahedral rather than octahedral or square planar. Why is this the case? Explain your reasoning. This is the case because Now consider a linear complex with only 2 ligands that lie on the z-axis. If you were to draw the d-orbital splitting for this complex, which orbital(s) would you expect to increase the most (be the highest) in energy? Least? Explain your reasoning