A 175.3 mg sample of C10H12O2 was dissolved in 1.50 g of chloroform (Kb = 3.63 °C/m). What is the boiling point of this solution.

Explanation:

Hello,

In this case, for the boiling point elevation, we have:

Whereas the van't Hoff factor for the given substance is 1 since is not ionizing.  Moreover, the molality is computed by:

In such a way, since the boiling point of pure chloroform is 61.2 °C, the boiling point of the solution is:

Regards.

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck