If Na was to form a 2 ion, from what orbital subshell would the second electron be lost?

2p

Explanation:

Sodium has an atomic number of 11, thus, the neutral atom has 11 electrons. The electron configuration is:

Na: 1s² 2s² 2p⁶ 3s¹

To gain stability, it loses an electron from its outer shell to form the cation Na⁺. Its electron configuration is:

Na⁺: 1s² 2s² 2p⁶

If it were to lose a second electron to form a Na²⁺ cation, the electron should be lost from the 2p orbital subshell and its electron configuration would be:

Na²⁺: 1s² 2s² 2p⁵

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante