A gas in a 6.2 mL cylinder has a pressure of 1.4 atmospheres. A piston is pushed in until the gas volume is 3.1 mL, while the temperature remains constant. What's the final pressure of the gas in the cylinder?

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Explanation:

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in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm