Calculate the [Cu2') remaining in 425 mL of a solution that was originally 0.366 M CuSO4 after passage of 2.68 A for 282 s and the deposition of Cu at the cathode.

Explanation:

Hello,

In this case, we may use the following equation in order to compute the moles of copper that are processed, considering it goes from Cu⁰ to Cu²⁺, so two electrons are transferred:

After that, we compute the initial moles of copper in the solution, considering that the concentration of copper (II) equals the concentration of copper:

In such a way, we can subtract the process moles to the initial moles to compute the remaining moles of copper:

Finally, the concentration is:

Regards.