The following reaction is second order in [A] and the rate constant is 0.025 M-1s-1: The concentration of A was 0.65 M at 33 s. The initial concentration of A was M. Select one:

a. 0.24

b. 1.2 � 10-2

c. 0.27

d. 2.4

e. 1.4

e. 1.4.

Explanation:

Hello,

In this case, for a second-order reaction, the integrated rate law is:

In such a way, for the given data, we compute the initial concentration as shown below in molar units (M):

Therefore, answer is e. 1.4 M.

Regards.

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.