What is the mass of 5.3 litres of carbon dioxide gas at STP

Explanation:

given volume =5.3 litres

as we know that 1 litre =1 dm3

therefore 5.3 litres =5.3 dm3

now moles =given mass /molar mass

so mass =moles*molar mass

in order to find mass of carbon we need to find moles

therefore moles=given volume/standard volume  standard volume at STP is 22.4 dm3

moles= 5.3/22.4

moles=0.236=0.24

now mass of carbon dioxide =moles*molar mass

mass = 0.24*44

mass=10.56kg

answer; /// i do believe that the correct answer is (c)nuclear bond

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

hope i !