When a 235 92U 92235U nucleus is bombarded by neutrons (10n01n) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. The following equation is an example of one such fission process: 235 92U+10n→AZBa+9436Kr+310n 92235U+01n→ZABa+3694Kr+301n Enter the isotope symbol for the barium (BaBa) nucleus in this reaction. Express your answer as an isotope.

139/56 Ba

Explanation:

In writing nuclear equations, there must be a balance of the mass and charge on both sides of the reaction equation. That is, the sum of masses on the lefthand side of the nuclear reaction equation must equal the sum of masses on the righthand side of the nuclear reaction equation. Similarly, the charges on the lefthand side of the nuclear reaction equation must equal the sum of the charges on the right hand side of the nuclear reaction equation.

Hence, the isotope of barium formed in the equation mentioned in the question is 139/56 Ba.

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