C6H12o6--->2c2O5OH+2H2O. How many grams of c6H12o6 are needed to form 7.50 gram of H2O5OH

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante