An experiment requires that enough SiCl2Br2 be used to yield of bromine . How much SiCl2Br2 must be weighed out?

42.75 grams of SiCl2Br2 must be weighed out

Explanation:

Here is the complete question:

An experiment requires that enough SiCl2Br2 be used to yield 13.2g of bromine . How much SiCl2Br2 must be weighed out?

Explanation:

First, we will determine the Molar mass of SiCl2Br2,

Si = 28.08, Cl = 35.45, Br = 79.90

Molar mass of SiCl2Br2 = 28.08 + 35.45(2) + 79.90(2)

= 258.78

Hence, the molar mass of SiCl2Br2 is 258.78 g/mol

If 79.90 grams of bromine is present in 258.78 grams of SiCl2Br2

Then, 13.2 grams of bromine will be present in grams of SiCl2Br2

= (13.2× 258.78) / 79.90

= 42.75 grams

Hence, 42.75 grams of SiCl2Br2 must be weighed out.

i believe it is a.) released into

explanation: