A piece of metal ore weighs 9.00 g. When a student places it into a graduated cylinder containing water, the liquid level rises from 21.25 mL to 26.47 mL. What is the density of the ore

1.72 g/ml

Explanation:

If our aim is to determine the density of the metal ore, then;

Mass of the metal ore= 9.00 g

Volume of the ore= volume of water displaced = 26.47 - 21.25 = 5.22 ml

Density of the ore= 9.00 g/5.22 mk

Density of the ore= 1.72 g/ml

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"