Chemistry, 31.08.2020 03:01 Evycin

The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a concentration of salt within the water, the density of water is 1.03 g/mL. Calculate the total mass of sodium chloride, in grams, contained in all the seawater in the world.

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Answer from: agray062103

Following are the calculation to the total mass of sodium chloride in grams:

Given:

Seawater volume $= 1.5 \times 10^{21}\ L\\\\$

Seawater density $= 1.03\ \frac{g}{mL}\\\\$

$\%$ of sodium chloride in seawater $= 3.5\ \%$

To find:

The total mass of sodium chloride in grams=?

Solution:

The total volume of seawater $= 1.5 \times 10^{21}\ L= 1.5 \times 10^{24}\ mL\\\\$

The density of seawater $= 1.03 \frac{g}{mL}$

$\therefore\\\\$

Seawater mass = Seawater volume $\times$ density

$= 1.5 \times 10^{24}\times 1.03 \ g\\\\= 1.545 \times 10^{24}\ g\\\\$

$\%$ of sodium chloride in seawater $= 3.5\ \%$

$\therefore\\\\$

Calculating the sodium chloride mass in Seawater:

$= 3.5\% \ \ of\ \ 1.545 \times 10^{24} \ g\\\\ =\frac{3.5}{100} \times 1.545 \times 10^{24}\ g\\\\= 5.4075 \times 10^{22} \ g\\\\$

Calculating the sodium chloride mass $= 5.4075 \times 10^{22} \ g\\\\$

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Answer from: maddoxlachowski

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater ( $m_{sw}$ ), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

$m_{sw} = \rho_{sw}\cdot V_{sw}$

Where:

$\rho_{sw}$ - Density of seawater, measured in grams per liters.

$V_{sw}$ - Volume of seawater, measured in liters.

If $V_{sw} = 1.5\times 10^{21}\,L$ and $\rho_{sw} = 1030\,\frac{g}{L}$ , then:

$m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)$

$m_{sw} = 1.545\times 10^{24}\,g$

The total mass of sodium chloride is determined by the following ratio:

$r = \frac{m_{NaCl}}{m_{sw}}$

$m_{NaCl} = r\cdot m_{sw}$

Given that $m_{sw} = 1.545\times 10^{24}\,g$ and r = 0.035 , the total mass of sodium chloride in all the seawater in the world is:

$m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)$

$m_{NaCl} = 5.408\times 10^{22}\,g$

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

Answer from: Quest

d is

Answer from: Quest

water molecules stay close to each other through cohesion, the collective action of hydrogen bonds between water molecules. cohesion plants draw water upwards from the root through the stem's transport tubes (xylem) to the leaf. this transport occurs even in large trees and against gravity. transpiration, evaporation of water from plant leaves, creates a tension on water molecules being pulled up from the stem and roots.

water also has high (the attraction of one substance to another) properties because of its polar nature. adhesion of water molecules to plant cell walls counteract gravity while water is transported from roots to leaves.

water exhibits a very high surface tension when compared to other liquids. surface tension is a property of a liquid that holds the surface together and allows it to resist an external force. by capillary action, the water forms concave menisci inside the pores. the high surface tension of water pulls the concavity outwards, generating enough force to lift water from the roots to the leaves of plants.

thus, cohesion, along with adhesion and surface tension creates a capillary action that keeps water molecules interacting and moving through the plants out to the leaf cells.

therefore, option d) is the correct answer.

explanation:

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The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride b...

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